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Physics Question on Viscosity

The velocity of water in a river is 18 km/hr18\, km/hr near the surface. If the river is 5 m5\, m deep, find the shearing stress between the horizontal layers of water. The co-efficient of viscosity of water =10−2= 10^{-2} poise.

A

10−1N/m210^{-1} N/m^2

B

10−2N/m210^{-2} N/m^2

C

10−3N/m210^{-3} N/m^2

D

10−4N/m210^{-4} N/m^2

Answer

10−3N/m210^{-3} N/m^2

Explanation

Solution

F=−nA dv/dxF =- nA \,dv / dx =−(10−3)(55)=−10−3=-\left(10^{-3}\right)\left(\frac{5}{5}\right)=-10^{-3} now stress =F/A=10−3= F / A =10^{-3}