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Question

Physics Question on Electromagnetic waves

The velocity of sound is v at 273 K. The temperature at which it is 2v is

A

2 ×\times 273 K

B

4 ×\times 273 K

C

8 ×\times 273 K

D

16 ×\times 273 K

Answer

4 ×\times 273 K

Explanation

Solution

Velocity of sound is given by
\hspace40mm v = \sqrt{\frac{3RT}{M}} = v ? T
Given, t = 273 K, v1=v,v2=2v.v_1 = v, v_2 = 2 v.
\therefore \hspace30mm \frac{v_1}{v_2} = \sqrt{\frac{T_1}{T_2}} \Rightarrow \, \, v_2 = \sqrt{\frac{T_2}{T_1}}v_1
\hspace40mm 2v = \sqrt{\frac{T_2}{273}v}
\Rightarrow \hspace30mm T_2 = 273 \times 4 \, K