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Question: The velocity of projection of oblique projectile is \((6\widehat{i} + 8\widehat{j})ms^{–1}\). The ho...

The velocity of projection of oblique projectile is (6i^+8j^)ms–1(6\widehat{i} + 8\widehat{j})ms^{–1}. The horizontal range of the projectile is-

A

4.9 m

B

9.6 m

C

19.6 m

D

14 m

Answer

9.6 m

Explanation

Solution

Q u cos q = 6 m/s u sin q = 8 m/s

\ R = 2(ucos⁡θ)(usin⁡θ)g\frac { 2 ( u \cos \theta ) ( u \sin \theta ) } { g } = 2(6)(8)10\frac { 2 ( 6 ) ( 8 ) } { 10 } = 9.6 m