Question
Question: The velocity of electrons in the fourth Bohr’s orbit of hydrogen is \(u\). The velocity of the elect...
The velocity of electrons in the fourth Bohr’s orbit of hydrogen is u. The velocity of the electron in the first orbit would be:
A.4u
B.16u
C.4u
D.16u
Solution
The Bohr’s model of hydrogen atom describes that the electron of the hydrogen moves in circular path orbit around the nucleus. In order to find the velocity of the electron in the fourth orbit of hydrogen,
We know that, angular momentum of electron,
⇒mvr=2πnh
Now, the r is the radius of the orbit and is equal to (πme2ε∘n2h2)
Thus,
⇒mv(πme2ε∘n2h2)=2πnh⇒v=2πnhε∘n2h2πe2⇒v=2ε∘nhe2 m/sec
Here,
e= Charge of electron which has a constant value of −1.6×10−19C
ε∘= Constant of proportionality
n= Number of hydrogen atom
h= Plank’s constant
Formula Used:
The velocity of electron in nth orbit of an atom is,
⇒v=2ε∘nhze2 m/sec
Where, z is the number of the orbit.
Complete Step by step solution:
Given that, z=4 and the velocity of the electron is u.
Thus, the equation becomes,
⇒u=2ε∘nh4e2
Here, n=1 as a hydrogen atom has only one electron.
⇒u=ε∘h2e2
Now, for the first orbit z=1, therefore the velocity of the electron is
⇒v=2ε∘he2
Now, comparing the value of u and v, we have
⇒v=4u
Thus, the velocity of the electron in the first orbit is 4u.
So, the correct answer is option A.
Note: Bohr’s model states that an atom consists of a small nucleus which is positively charged and is surrounded by the electrons which are negatively charged. These electrons revolve around the nucleus in a circular path known as orbit or shells. Each orbit and shell of an atom has a fixed amount of energy.