Question

The velocity of a particle is $v = v_0 + gt + ft^2$. If its position is $x = 0$ at $t = 0$, then its displacement after unit time $(t = 1)$ is

• A. $v_0 + 2g + 3f$
• B. $v_0 + g/2 + f/3$
• C. $v_0 + g + f$
• D. $v_0 + g/2 + f$

Answer 1

Answer: (B)

$v_0 + g/2 + f/3$

Answer 2

$\int\limits^{x}_{{0}}dx=\int\limits^{1}_{{0}}(V_0+gt+ft^2)dt$ $x=v_{0}+g\left(\frac{1}{2}\right)+f \left(\frac{1}{3}\right)$