Question

The velocity of a particle executing SHM varies with displacement $(x)$ as $4 v^2=50-x^2$ The time period of oscillations is $\frac{x}{7} s$ The value of $x$ is _______(Take $\pi =\frac{22}{7}$)

Answer 1

The correct answer is 88.
4v2=50−x2
⇒v=21​50−x2​
ω=21​
T=ω2π​=4π=788​
x=88