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Question: The velocity of a bullet is reduced from 200m/s to 100m/s while travelling through a wooden block of...

The velocity of a bullet is reduced from 200m/s to 100m/s while travelling through a wooden block of thickness 10cm. The retardation, assuming it to be uniform, will be

A

10×10410 \times 10^{4} m/s2

B

12×10412 \times 10^{4} m/s2

C

13.5×10413.5 \times 10^{4} m/s2

D

15×10415 \times 10^{4} m/s2

Answer

15×10415 \times 10^{4} m/s2

Explanation

Solution

u=200m/su = 200m/s, v=100m/sv = 100m/s, s=0.1ms = 0.1m

a=u2−v22s=(200)2−(100)22×0.1=15×104m/s2a = \frac{u^{2} - v^{2}}{2s} = \frac{(200)^{2} - (100)^{2}}{2 \times 0.1} = 15 \times 10^{4}m/s^{2}