Question
Question: The velocity of a bullet is reduced from \(200{\text{ }}m{s^{ - 1}}\)to\(100{\text{ }}m{s^{ - 1}}\) ...
The velocity of a bullet is reduced from 200 ms−1to100 ms−1 while travelling through a wooden plank of thickness 10 cm. The retardation, assuming it to be uniform, will be
A) 10×104m/s2
B) 12×104m/s2
C) 13.5×104m/s2
D) 15×104m/s2
Solution
Hint
Retardation is nothing but the acceleration of a body in the negative direction. It is defined the same way as acceleration as the rate of change of velocity with respect to time. We need to apply newton’s equations of motion to find the retardation in terms of distance travelled.
Complete step by step answer
According to newton’s equations of motion, we know that:
v2 − u2 = 2as
Where, v is the final velocity of the body,
u in the initial velocity of the body,
a is the acceleration of the body,
And s is the distance travelled during this time.
In the question we are given v, u and s. All we need to find is acceleration of the body is the negative direction.
Substituting the values,
⇒1002 − 2002 = 2a(0.1) ⇒10000 − 40000 = 0.2a ⇒−0.230000 = a ⇒a=15×104m/s2
Therefore, the option with the correct answer is option (D).
Note
One can easily make mistakes in converting the units. In this question we see that the speeds are in meters per second but the thickness is in centimeters. Each equation of motion is defined as the relation between v, u, a, s and t; but taking only 4 at a time. So, if we are given any 3 of these quantities, we can easily find the 4th one by substituting.