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Question: The velocity of a body of mass 5kg changes from 30 m/s to 40 m/s. Find the corresponding increase in...

The velocity of a body of mass 5kg changes from 30 m/s to 40 m/s. Find the corresponding increase in its momentum.
A) 50 kg m/s
B) 75 kg m/s
C) 150 kg m/s
D) 300 kg m/s

Explanation

Solution

Linear momentum of a body is the product of the mass of the body and its velocity. It describes how much mass is present in how much motion.

Formulas used:
The momentum pp of a body of mass mm and velocity vv is given by, p=mvp = mv

Complete step by step answer:
Step 1: List the data given in the question.
The mass of the body is m=5kgm = 5{\text{kg}} . The change in velocity is from 30 m/s to 40 m/s.
Let vi{v_i} be the initial velocity and vf{v_f} be the final velocity of the body. Then we have, vi=30m/s{v_i} = 30{\text{m/s}} and vf=40m/s{v_f} = 40{\text{m/s}} .
Step 2: Calculate the initial momentum.
The momentum pp of a body of mass mm and velocity vv is given by, p=mvp = mv -------- (1)
Let pi{p_i} be the initial momentum. Then equation (1) will be pi=mvi{p_i} = m{v_i} .
Substituting the values for m=5kgm = 5{\text{kg}} and vi=30m/s{v_i} = 30{\text{m/s}} in the above equation we get, pi=5×30=150 kg m/s{p_i} = 5 \times 30 = 150{\text{ kg m/s}} .
Thus the initial momentum is pi=150 kg m/s{p_i} = 150{\text{ kg m/s}} .
Step 3: Calculate the final momentum.
The momentum pp of a body of mass mm and velocity vv is given by, p=mvp = mv -------- (1)
Let pf{p_f} be the final momentum. Then equation (1) will be pf=mvf{p_f} = m{v_f} .
Substituting the values for m=5kgm = 5{\text{kg}} and vf=40m/s{v_f} = 40{\text{m/s}} in the above equation we get, pf=5×40=200 kg m/s{p_f} = 5 \times 40 = 200{\text{ kg m/s}} .
Thus the initial momentum is pf=200 kg m/s{p_f} = 200{\text{ kg m/s}} .
Step 4: Find the change in momentum.
We have the initial momentum as pi=150 kg m/s{p_i} = 150{\text{ kg m/s}} and the final momentum as pf=200 kg m/s{p_f} = 200{\text{ kg m/s}} .
Then the change in momentum will be Δp=pfpi\Delta p = {p_f} - {p_i} -------- (2).
Substituting the values of initial momentum and final momentum in equation (2) we get, Δp=200150=50 kg m/s\Delta p = 200 - 150 = 50{\text{ kg m/s}}

Therefore, the increase in momentum is 50 kg m/s.

Note:
- The change in momentum is referred to as impulse.
- A change in momentum occurs when a force acts on a body for a given time. If force is in a direction opposite to the body’s velocity, then the body slows down.
- If the force acts in the same direction in which the body moves, then the body will speed up. In our problem, the momentum increases since the velocity of the body increases. This suggests that a force acted for a given time in the direction of the body’s motion.