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Question: The velocity of a body moving with a uniform acceleration of \(2 \mathrm {~m} . / \mathrm { sec } ^...

The velocity of a body moving with a uniform acceleration of 2 m./sec22 \mathrm {~m} . / \mathrm { sec } ^ { 2 } is 10 m/sec10 \mathrm {~m} / \mathrm { sec } . Its velocity after an interval of 4 sec is

A

12 m/sec12 \mathrm {~m} / \mathrm { sec }

B

14 m/sec14 \mathrm {~m} / \mathrm { sec }

C

16 m/sec16 \mathrm {~m} / \mathrm { sec }

D

18 m/sec18 \mathrm {~m} / \mathrm { sec }

Answer

18 m/sec18 \mathrm {~m} / \mathrm { sec }

Explanation

Solution

v=u+at=10+2×4=18 m/secv = u + a t = 10 + 2 \times 4 = 18 \mathrm {~m} / \mathrm { sec }