Question
Question: The velocity of a body at the end of \(4\;{\rm{seconds}}\) is \(26\;{\rm{m}}{{\rm{s}}^{ - 1}}\), a...
The velocity of a body at the end of 4seconds is
26ms−1, at the end of 12seconds is 58ms−1 and at the end of 22seconds is
98ms−1. The body is moving with:-
(A) Uniform acceleration
(B) Uniform speed
(C) Uniform velocity
(D) Uniform displacement
Solution
In this question, the body's velocity is given to us at a different time interval, so we will use the equation of motion at a different time interval. The various equations will give us information about the acceleration, speed, velocity, and displacement of the body.
Complete step by step answer:
It is given to us that velocity of the body at the end of 4second is 26ms−1, at the end of 12seconds is 58ms−1 and at the end of 22second is 98ms−1. So, write the equation of motion for the condition of the body after 4seconds.
⇒v=u+at
Here v is the velocity of the body after 4seconds and u is the initial velocity of the body, a is the body's acceleration in the first condition, and t is the time.
Substitute the values in the above equation.
Therefore, we get
⇒26ms−1=0+a(4s) …… (1)
Write the equation of motion for the second condition when body’s velocity is ⇒58ms−1 at the end of 12seconds. So,
⇒v=u+at
Here we will substitute the values in the above equation that are given in the second condition. So,
⇒58ms−1=u+a(12s) …… (2)
Write the equation of motion for the third condition when body’s velocity is ⇒98ms−1 at the end of 22seconds. So,
⇒v=u+at
Here we will substitute the values in the above equation that are given in the third condition. So,
⇒58ms−1=u+a(12s) …… (3)
Use equations (1) and (2) to determine the acceleration of the body.
Therefore, we get
⇒26ms−1=(58ms−1−a(12s))+a(4s) ⇒a(12s)−a(4s)=58ms−1−26ms−1 ⇒a(8s)=32ms−1 ⇒a=4ms−2
We use equations (2) and (3) to determine the body's acceleration at different times.
⇒58ms−1=(98ms−1−a(22s))+a(12s) ⇒a(22s)−a(12s)=98ms−1−56ms−1 ⇒a(10s)=40ms−1 ⇒a=4ms−2
Therefore, the acceleration values are the same at two different times, so the body's acceleration is uniform, and option (A) is correct.
Note: we used the first equation of motion in the solution because information about the displacement is not given in the question. The question only gives information about velocity and time. The second and third equation of motion consists of displacement terms, so it's become difficult for us to determine the correct answer.