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Question: The velocity constant of a reaction at 290 K was found to be \(3.2 \times 10^{- 3}\). At 300 K it wi...

The velocity constant of a reaction at 290 K was found to be 3.2×10−33.2 \times 10^{- 3}. At 300 K it will be.

A

1.28×10−21.28 \times 10^{- 2}

B

6.4×10−36.4 \times 10^{- 3}

C

9.6×10−39.6 \times 10^{- 3}

D

3.2×10−43.2 \times 10^{- 4}

Answer

6.4×10−36.4 \times 10^{- 3}

Explanation

Solution

As we know that the velocity constant become double by increasing the temperature by 10°C so if at 290 K, velocity constant =3.2×10−3= 3.2 \times 10^{- 3} then at 300 K, velocity constant

=2(K290)=2×3.2×10−3=6.4×10−3= 2(K_{290}) = 2 \times 3.2 \times 10^{- 3} = 6.4 \times 10^{- 3}.