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Question: The velocity at which the mass of a particle becomes twice its rest mass will be...

The velocity at which the mass of a particle becomes twice its rest mass will be

A

2C3\frac{2C}{3}

B

C2\frac{C}{2}

C

C32\frac{C\sqrt{3}}{2}

D

3C4\frac{3C}{4}

Answer

C32\frac{C\sqrt{3}}{2}

Explanation

Solution

m = m01–v2c2\frac{m_{0}}{\sqrt{1–\frac{v^{2}}{c^{2}}}}= 2m0\ 1 – v2c2\frac{v^{2}}{c^{2}}= 14\frac{1}{4} Ž v2c2\frac{v^{2}}{c^{2}}= 34\frac{3}{4}

\ v = c32\frac{c\sqrt{3}}{2}