Question

The velocity associated with a proton moving in a potential difference of 1000 V is 4.37×105 ms–1. If the hockey ball of mass 0.1 kg is moving with this velocity, calculate the wavelength associated with this velocity.

Answer 1

According to de Broglie's expression,
λ = $\frac{h}{mv}$
Substituting the values in the expression,
λ = $\frac{6.626×10^{-34} Js}{(0.1 kg)(4.37 × 10^5 ms^{-1})}$
λ = 1.516 × 10-38 m