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Question

Physics Question on Uniform Circular Motion

The velocity and acceleration vectors of a particle undergoing circular motion are v=2m^/s\vec{ v }=2 \hat{ m } / s and a=21^+4j^m/s2\vec{ a }=2 \hat{1}+4 \hat{ j } m / s ^{2} respectively at an instant of time. The radius of the circle is

A

1 m

B

2 m

C

3 m

D

4 m

Answer

1 m

Explanation

Solution

Given,
v=2i^ms1vx=2,vy=0\vec{ v }=2{\hat{i}ms ^{-1}} v _{ x }=2,\,\, v _{ y }=0
a=(2i^+4j^)ms2ax=2,ay=4\vec{ a }=(2 \hat{i}+4 \hat{j}) ms ^{-2} a _{ x }=2, \,\,a _{ y }=4
Tangential velocity in circular motion give, centripetal acceleration toward center Centripetal acceleration is normal to the tangential velocity
ay=vx2ra_{y}=\frac{v_{x}^{2}}{|r|}
r=vx2ay=224=1m| r |=\frac{ v _{ x }^{2}}{ a _{ y }}=\frac{2^{2}}{4}=1\, m
Hence, radius of circle is 1m1\, m