Solveeit Logo

Question

Chemistry Question on Quantum Mechanical Model of Atom

The velocities of two particles AA and BB are 0.050.05 and 0.02ms10.02\, ms^{-1} respectively. The mass of BB is five times the mass of AA. The ratio of their de- Broglie's wavelength is

A

2:01

B

#VALUE!

C

1:01

D

4:01

Answer

2:01

Explanation

Solution

Given, velocity of particle A=0.05ms1A=0.05\, ms ^{-1}
Velocity of particle B=0.02ms1B=0.02\, ms ^{-1}
Let the mass of particle A=xA=x
\therefore The mass of particle B=5xB=5 x
de-Broglie's equation is
λ=hmv\lambda=\frac{h}{m v}
For particle AA
λA=hx×0.05...(i)\lambda_{A}=\frac{h}{x \times 0.05} ...(i)
For particle B
λ=h5x×0.02...(ii)\lambda=\frac{h}{5 x \times 0.02}...(ii)
Eq (i)/(ii)
λAλB=5x×0.02x×0.05\frac{\lambda_{A}}{\lambda_{B}}=\frac{5 x \times 0.02}{x \times 0.05}
λAλB=21\frac{\lambda_{A}}{\lambda_{B}}=\frac{2}{1}
Or 2:12: 1