Question

The vector equation of the line joining the points (2, 1, 3) and (-2, 4, 1) is

• A. $\overrightarrow{r} = 2\hat{i}+\hat{j}+3\hat{k}+\lambda(-4\hat{i}+3\hat{j}-2\hat{k})$
• B. $\overrightarrow{r} = 2\hat{i}+\hat{j}+3\hat{k}+\lambda(4\hat{i}+3\hat{j}+2\hat{k})$
• C. $\overrightarrow{r} = -2\hat{i}+\hat{j}+3\hat{k}+\lambda(-4\hat{i}-3\hat{j}-2\hat{k})$
• D. $\overrightarrow{r} = 2\hat{i}+\hat{j}+3\hat{k}+\lambda(3\hat{i}-4\hat{j}-2\hat{k})$
• E. $\overrightarrow{r} = -4\hat{i}+3\hat{j}-2\hat{k}+\lambda(2\hat{i}+\hat{j}+3\hat{k})$

Answer 1

Answer: (A)

$\overrightarrow{r} = 2\hat{i}+\hat{j}+3\hat{k}+\lambda(-4\hat{i}+3\hat{j}-2\hat{k})$

Answer 2

The correct option is (A): $\overrightarrow{r} = 2\hat{i}+\hat{j}+3\hat{k}+\lambda(-4\hat{i}+3\hat{j}-2\hat{k})$