Question
Question: The vector 3-4i is turned anticlockwise through an angle of \({{180}^{\circ }}\) and stretched 2.5 t...
The vector 3-4i is turned anticlockwise through an angle of 180∘ and stretched 2.5 times. The complex number corresponding to the newly obtained vector is ..
& A.\dfrac{-15}{2}+10i \\\ & B.\dfrac{15}{2}+10i \\\ & C.\dfrac{-15}{2}-10i \\\ & D.\dfrac{15}{2}-10i \\\ \end{aligned}$$Solution
For solving this question, we first need to understand the signs in the complex plane. Since every complex plane is of the form x+iy. So a complex plane is the same as an argand plane where x is x and y is y axis. First we will find the quadrant in which the current vector is lying. Then we will find the quadrant if the vector is rotated through an angle 180∘. Using the quadrant, we will change the sign of the vector and at last we will multiply obtained vector by 2.5 to get the required vector.
Complete step-by-step answer:
Let us understand the complex plane first. In the complex plane the horizontal axis is the x axis and vertical axis is y axis. It looks like this:
Complex numbers of the form x+iy lie in I quadrant, -x+iy lie in II quadrant, -x-iy lies in III quadrant and x-iy lies in IV quadrant.
Here we are given complex numbers as 3-4i. It is of the form x-iy. So it lies in the IV quadrant. If we turn the vector anticlockwise to 180∘ our new vector will lie in II quadrant where vectors are of form -x+iy. So our vector becomes -3+4i.
Now, we have to stretch it 2.5 times, so our new vector becomes 2.5 times the original vector. So required complex number will be,