Question

The variation of applied potential and current flowing through a given wire is shown in figure. The length of wire is 31.4 cm. The diameter of wire is measured as 2.4 cm. The resistivity of the given wire is measured as x × 10–3Ω cm. The value of x is____. [Take π = 3.14]

Answer 1

The correct answer is: 144

Resistance = tan 45° = 1 Ω

$⇒1=\frac{pl}{A}$

⇒$p=\frac{\pi(1.2 cm)^2}{31.4 cm}=1.44×10^{−1} Ω\,cm$

⇒ x = 144