Question

The variance of the following continuous frequency distribution is

• A. 201
• B. 62
• C. 19
• D. 84

Answer 1

Answer: (D)

84

Answer 2

Given $\because \bar{x}=\frac{\sum x_{i} f_{i}}{N}=\frac{190}{10}=19$ $\therefore$ Variance $(\sigma)^{2}=\frac{1}{N} \Sigma f_{i}\left(\bar{x}-x_{i}\right)^{2}$ $=\frac{1}{10}(840)=84$