Solveeit Logo

Question

Question: The variance of the first 50 even natural numbers is______....

The variance of the first 50 even natural numbers is______.

Explanation

Solution

Here we will first write the general form of the even numbers. Then we will write the actual numbers and find the value of the mean of the numbers. Then we will put the value of mean in the formula of the variance to get the variance of the first 50 even natural numbers. Even numbers are the numbers that are exactly divisible by 2.

Formula used:
Variance σ2=1nxi2(xˉ)2{\sigma ^2} = \dfrac{1}{n}\sum {{x_i}^2} - {\left( {\bar x} \right)^2}, where xi{x_i} is the ith{i^{th}} value, nn is the number of terms of the series and xˉ\bar x is the mean value of the series.

Complete Step by Step Solution:
General form of the even numbers is 2r2r where, rr varies from 1, 2, 3 to infinity.
It is given that the numbers are the first 50 even numbers. Therefore n=50n = 50
So the given range of the numbers is 2, 4, 6, 8, 10, 12…., 100.
Firstly we will find the value of the mean of the numbers. Therefore, we get
Mean xˉ=xin\bar x = \dfrac{{\sum {{x_i}} }}{n}
xˉ=r=1r=502rn\Rightarrow \bar x = \dfrac{{\sum\limits_{r = 1}^{r = 50} {2r} }}{n}
Now by putting the values in the formula of the mean, we get
xˉ=2+4+6+8+10+12+......+10050\Rightarrow \bar x = \dfrac{{2 + 4 + 6 + 8 + 10 + 12 + ...... + 100}}{{50}}
xˉ=50×5150\Rightarrow \bar x = \dfrac{{50 \times 51}}{{50}}
Simplifying the expression, we get
xˉ=51\Rightarrow \bar x = 51
Now we will put the value of mean in the variance formula and by using that formula of variance we will calculate the value of the variance. Therefore, we get
σ2=r=1r=504r2n(51)2{\sigma ^2} = \dfrac{{\sum\limits_{r = 1}^{r = 50} {4{r^2}} }}{n} - {\left( {51} \right)^2}
Now by solving the above equation of the variance, we get
Variance, σ2=833{\sigma ^2} = 833

Hence the variance of the first 50 even natural numbers is 833.

Note:
we should know that the square root of the variance is equal to the standard deviation of the data.
Standarddeviation=VarianceStandard\,deviation = \sqrt {Variance}
Standard deviation is defined as the measure of the variation of the numbers within the given set of numbers. Standard deviation is used to check the range of deviation of the data from the mean of the data. Wider the range of the data from the mean in a set of numbers, then higher will be the standard deviation and lower the range of the data in a set of numbers then lower will be the standard deviation of the data.