Question

The variance of first n odd natural numbers is $\frac{n^{2}-1}{3}$ : The sum of first n odd natural number is $n^2$ and the sum of square of first n odd natural numbers is $\frac{n\left(4n^{2}-1\right)}{3}.$

• A. Statement 1 is true, Statement 2 is false.
• B. Statement 1 is true, Statement 2 is true; Statement 2 is not a correct explanation for Statement 1.
• C. Statement 1 is false, Statement 2 is true.
• D. Statement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1.

Answer 1

Answer: (A)

Statement 1 is true, Statement 2 is false.

Answer 2

Statement 2 : Sum of first n odd natural numbers is not equal to $n^2$. So, statement - 2 is false.