The variance of first n odd natural numbers is (\frac{n^2 -... | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

The variance of first n odd natural numbers is $\frac{n^2 - 1}{3}$ . The sum of first n odd natural number is $n^2$ and the sum of square of first n odd natural numbers is $\frac{ n (4n^2 + 1)}{3}$ .

A

Statement 1 is true, Statement 2 is false

B

Statement 1 is true, Statement 2 is true; Statement 2 is not a correct explanation for Statement 1

C

Statement 1 is false, Statement 2 is true

D

Statement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1

Answer

Statement 1 is true, Statement 2 is false

Explanation

Solution

The correct option is A , Statement 2: Sum of first n odd natural numbers is not equal to $n^2$ . So, statement - 2 is false.