Solveeit Logo

Question

Mathematics Question on Variance and Standard Deviation

The variance of first 5050 even natural numbers is

A

8334 \frac{ 833}{ 4}

B

833833

C

437437

D

4374 \frac{437}{4}

Answer

833833

Explanation

Solution

Variance =Σxi2N(xˉ)2=\frac{\Sigma x_{i}^{2}}{N}-(\bar{x})^{2}
σ2=22+42++100250(2+4++10050)2\sigma^{2}= \frac{2^{2}+4^{2}+\ldots+100^{2}}{50}-\left(\frac{2+4+\ldots+100}{50}\right)^{2}
=4(12+22+32+.+502)50(51)2= \frac{4\left(1^{2}+2^{2}+3^{2}+\ldots .+50^{2}\right)}{50}-(51)^{2}
=4(50×51×10150×6)(51)2=4\left(\frac{50 \times 51 \times 101}{50 \times 6}\right)-(51)^{2}
=34342601=3434-2601
σ2=833\Rightarrow \sigma^{2} =833