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Question

Question: The vapour of a carboxylic acid *HA* when passed over \(\mathrm { MnO } _ { 2 }\) at 573 *K* yields ...

The vapour of a carboxylic acid HA when passed over MnO2\mathrm { MnO } _ { 2 } at 573 K yields propanone. The acid HA is

A

Methanoic acid

B

Ethanoic acid

C

Propanoic acid

D

Butanoic acid

Answer

Propanoic acid

Explanation

Solution

+CH3COOH+ \mathrm { CH } _ { 3 } \mathrm { COOH }