Question

The vapour density of $N_2O_4$ at a certain temperature is 30. What is the percentage dissociation of $N_2O_4$ at this temperature ?

• A. 0.533
• B. 1.066
• C. 0.267
• D. None.

Answer 1

Answer: (A)

0.533

Answer 2

Mol. wt. of $N_2O_4$ = 92 Vapour density, D = $\frac{92}{2}$ = 46 ${N_2O_4 (g) <=> 2NO_2 (g)}$ Here $y = 2$ $d = 30$ $x = \frac{D-d}{d(y-1)}$ = 0.533 = 53.3 %