Question

The vapour density of a mixture containing ${NO2}$ and ${N2O4}$ is 38.3 at ${27^{\circ}C}$. What will be the mole of ${NO_2}$ in 100 mole mixture.

• A. 76.6 mol
• B. 33.48 mol
• C. 50 mol
• D. 46 mol

Answer 1

Answer: (B)

33.48 mol

Answer 2

Given, Vapour density of mixture $NO_2$ and $N_2O_4 = 38.3$ Temperature $= 27^??$ Moles of $NO_2 + 2NO_2$ mixture $= 100$ $3(NO_2)=100$ $NO_{2}=\frac{100}{3}=33.4$ mol