Question

The van't Hoff factor indicates the number of solute particles produced per formula unit that dissolves.
If true enter $1$ , if false enter $0$ .

Answer 1

Hint : It is a property which provides us insight on the effect of solutes on colligative properties of solutions. It is denoted by the symbol $i$ . it is the ratio of the concentration of particles formed when a substance is dissolved to concentration of substance by mass. It is the extent to which a substance associates or dissociates in a solution.

Complete Step By Step Answer:
For example, when a non-electrolytic substance is dissolved in water, the value of $i$ is generally $1$ . However, when an ionic compound forms a solution in water, the value of $i$ is equal to the total number of ions present in one formula unit of the substance.
$Cac{l_2}$ dissolves one calcium ion and two chloride ions in a solution. This causes the Van’t Hoff factor to become $3$ . But sometimes there is an association between ions in the solutions which leads to a decrease in total number of particles in the solution.
It explains the dissociation and formation of ions when solutes are made to dissolve in solvent. Since colligative properties depend only on the number of solute particles, the dissociation of solute molecules into ions results in an increase in the number of particles. This affects the colligative properties.
${\text{The Van't Hoff factor }}(i) =$
$= \dfrac{{{\text{Number of solute particles present in solution}}}}{{{\text{theoretical numbers of solute particles due to solutions of non electrolyte}}}}$
$= \dfrac{{n(observed)}}{{n(theoretical)}}$
Thus it does indicate it.

Note :
It is important to note that the measured value of the Van’t Hoff factor for electrolytic solutions is generally lower than the predicted value (due to the pairing of ions). The greater the charge present on the ions, the greater the deviation. The joining of two or more particles resulting in the formation of one entity is called association. For example, the dimerization of carboxylic acids when dissolved in benzene happens due to association.