Question

The values of x in the interval $[0,\pi]$ such that $sin 2x = \frac{\sqrt3}2$

• A. $\frac{\pi}6, \frac{\pi}3$
• B. $\frac{\pi}6,\frac{2\pi}3$
• C. $\frac{\pi}3,\frac{2\pi}3$
• D. $\frac{\pi}6,\frac{5\pi}6$
• E. $\frac{\pi}3,\frac{5\pi}6$

Answer 1

Answer: (A)

$\frac{\pi}6, \frac{\pi}3$

Answer 2

The correct option is (A): $\frac{\pi}6, \frac{\pi}3$