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Question: The values of 'a' for which both roots of the equation (a + 1)x<sup>2</sup> –3ax + 4a = 0 are greate...

The values of 'a' for which both roots of the equation (a + 1)x2 –3ax + 4a = 0 are greater than unity:

A

[167,0)\left\lbrack \frac{- 16}{7},0 \right)

B

(12,0]\left( \frac{- 1}{2},0 \right\rbrack

C

[167,1)\left\lbrack \frac{- 16}{7}, - 1 \right)

D

(1,12)\left( - 1,\frac{- 1}{2} \right)

Answer

[167,1)\left\lbrack \frac{- 16}{7}, - 1 \right)

Explanation

Solution

D ≥ 0 & 3aa+1\frac{3a}{a + 1}> 2 & (a + 1) (2a + 1) > 0

167\frac{- 16}{7} ≤ a ≤ 0 & a < –1, a > 2 &

a < – 1, a > 12\frac{- 1}{2} ⇒ a ∈ [167,1)\left\lbrack \frac{- 16}{7}, - 1 \right)