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Question: The value of\(f( - 1) = f(y) = \log y,\) is...

The value off(−1)=f(y)=log⁡y,f( - 1) = f(y) = \log y, is

A

a2 cos a + 2a sin a

B

a2sin a + 2a cos a

C

a2 cos a + a2 sin a

D

None of these

Answer

a2 cos a + 2a sin a

Explanation

Solution

Here lim⁡x→0\lim _ { x \rightarrow 0 } (a+x)2sin⁡(a+x)−a2sin⁡ax\frac { ( a + x ) ^ { 2 } \sin ( a + x ) - a ^ { 2 } \sin a } { x }

= (a2 sin a) = a2 cos a + 2a sin a