Question
Question: The value of \({{Z}_{c}}\) at \({{T}_{c}}\), \({{P}_{c}}\) and \({{V}_{c}}\) is: A. 3/8 B. 4/8 ...
The value of Zc at Tc, Pc and Vc is:
A. 3/8
B. 4/8
C. 1
D. 0
Solution
Recall the meaning of compressibility factor, critical temperature, pressure, and volume. Think about how all of these are related and expressed in terms of the Vander Waals constants.
Complete answer:
Here, Zc is the compressibility factor which shows the deviation of the behaviour of a real gas from the behaviour of an ideal gas. The Vander Waals constants ‘a’ and ‘b’ are used to calculate the value of Zc at critical temperature, pressure, and volume.
From here onwards we will refer to ‘a’ and ‘b’ as Van Der Waals constants, Tc as critical temperature, Pc as critical pressure, and Vc as critical volume.
- Critical temperature (Tc): It is the temperature above which the gas cannot be liquefied at any pressure. It’s relation to the Vander Waals constants is:
Tc=27Rb8a
- Critical pressure (Pc): It is the pressure required to liquefy a real gas at its critical temperature. It’s relation to the Vander Waals constants is:
Pc=27b2a
- Critical volume (Vc): It is the volume of one mole of the real gas liquefied at the critical temperature. It’s relation to the Vander Waals constants is:
Vc=3b
Now, to calculate the compressibility factor, we need to put these values of Tc, Pc and Vc into the formula calculating Zc. The formula for compressibility factor is:
Zc=RTcPcVc
Now, putting the values, we get:
Zc=R×27Rb8a27b2a×3b
Zc=27b8a9ba
Zc=9ba×8a27b
Zc=83
Hence, the answer is ‘A. 3/8’
Note: The compressibility factor in the critical state of any real gas is known to be 3/8.
The relation between the critical states and the Vander Waals constant is derived using Van Der Waals real gas equation:
[P+V2an2]+[V−nb]=nRT