Solveeit Logo

Question

Question: The value of \(x^{2} - 6x + 13\)for which \(x^{2} - 3x + 3\)has equal and real roots are....

The value of x26x+13x^{2} - 6x + 13for which x23x+3x^{2} - 3x + 3has equal and real roots are.

A

–9 and –7

B

9 and 7

C

–9 and 7

D

9 and –7

Answer

9 and –7

Explanation

Solution

Equation β\beta has equal and real roots, then 2x23x+4=02x^{2} - 3x + 4 = 0.

4x2+7x+16=04x^{2} + 7x + 16 = 04x2+7x+6=04x^{2} + 7x + 6 = 0

4x2+7x+1=04x27x+16=04x^{2} + 7x + 1 = 04x^{2} - 7x + 16 = 0.