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Question: The value of x satisfying the logarithmic equation \({{\log }_{3}}\left( {{\log }_{2}}\left( {{\log ...

The value of x satisfying the logarithmic equation log3(log2(log3x))=1{{\log }_{3}}\left( {{\log }_{2}}\left( {{\log }_{3}}x \right) \right)=1 is
[a] x = 6561
[b] x = 65536
[c] x = 81
[d] x= 243

Explanation

Solution

Hint: Assume log2(log3x)=t{{\log }_{2}}\left( {{\log }_{3}}x \right)=t. Use the fact that if loga(x)=y{{\log }_{a}}\left( x \right)=y, then x=ayx={{a}^{y}}. Hence find the value of t. Now assume log3x=z{{\log }_{3}}x=z. Use the fact that if loga(x)=y{{\log }_{a}}\left( x \right)=y, then x=ayx={{a}^{y}}. Hence find the value of z. Again use the fact that if loga(x)=y{{\log }_{a}}\left( x \right)=y, then x=ayx={{a}^{y}} and hence find the value of x. Verify your answer.

Complete step-by-step answer:
Let log2(log3x)=t{{\log }_{2}}\left( {{\log }_{3}}x \right)=t.
Hence, we have
log3t=1{{\log }_{3}}t=1
We know that if loga(x)=y{{\log }_{a}}\left( x \right)=y, then x=ayx={{a}^{y}}.
Using the above property, we get
t=31=3t={{3}^{1}}=3
Hence, we have t = 3
Reverting to the original variable, we get
log2(log3x)=3{{\log }_{2}}\left( {{\log }_{3}}x \right)=3
Put log3x=z{{\log }_{3}}x=z
Hence, we have
log2z=3{{\log }_{2}}z=3
We know that if loga(x)=y{{\log }_{a}}\left( x \right)=y, then x=ayx={{a}^{y}}.
Using the above property, we get
z=23=8z={{2}^{3}}=8
Hence, we have z=8
Reverting to the original variable, we get
log3x=8{{\log }_{3}}x=8
We know that if loga(x)=y{{\log }_{a}}\left( x \right)=y, then x=ayx={{a}^{y}}.
Using the above property, we get
x=38=6561x={{3}^{8}}=6561
Hence, we have x = 6561.
Hence the solution of the given equation is x=6561
Hence, we conclude that option [a] is correct.

Note: [1] Verification:
We can verify the correctness of our solution by checking that the value of log3(log2(log3x)){{\log }_{3}}\left( {{\log }_{2}}\left( {{\log }_{3}}x \right) \right) at x = 6561 is 1
We have
log36561=log338{{\log }_{3}}6561={{\log }_{3}}{{3}^{8}}
We know that logaan=n{{\log }_{a}}{{a}^{n}}=n
Hence, we have
log36561=8{{\log }_{3}}6561=8
Applying log2{{\log }_{2}} on both sides of the equation, we get
log2(log36561)=log28=log223{{\log }_{2}}\left( {{\log }_{3}}6561 \right)={{\log }_{2}}8={{\log }_{2}}{{2}^{3}}
We know that logaan=n{{\log }_{a}}{{a}^{n}}=n
Hence, we have
log2(log36561)=3{{\log }_{2}}\left( {{\log }_{3}}6561 \right)=3
Applying log3{{\log }_{3}} on both sides of the equation, we get
log3(log2(log36561))=log33=1{{\log }_{3}}\left( {{\log }_{2}}\left( {{\log }_{3}}6561 \right) \right)={{\log }_{3}}3=1
Hence our solution is verified to be correct.
[2] A common mistake done by students is that they report solutions without verifying that the solutions are in the domain of the function or not. In solving questions involving inverse trigonometric functions and logarithmic functions, special care should be given to the domain of the functions involved. One can, however, avoid calculation of domain, just by verifying each solution at the end and discarding those solutions which do not satisfy the equation because they lead to values inside functions which are not in the domain of those functions.