Question

The value of x in the given equation

$\frac{p\beta - \alpha q}{q - \beta}$is.

• A. $x^{2} - cx + d = 0$
• B. $x^{2} - ax + b = 0$
• C. $2(b + d) =$
• D. $a + c$

Answer 1

Answer: (B)

$x^{2} - ax + b = 0$

Answer 2

Equation, $1 - \sqrt{2}$

⇒ $1 + \sqrt{2}$

⇒ $1 \pm \sqrt{2}$

⇒ $2^{x + 2}27^{x/(x - 1)} = 9$ ⇒ $1 - \log_{2}3,2$

Taking log both sides

⇒ $\log_{2}\left( \frac{2}{3} \right),\mspace{6mu} 1$

⇒ $2, - 2$

⇒ $- 2,\mspace{6mu} 1 - \frac{\log 3}{\log 2}$

⇒ $\alpha$

⇒ $\beta$ ⇒ $x^{2} + x + 1 = 0$

$\alpha^{19},\beta^{7}$

Trick : Cheak the equation with options then only option (2) satisfies the equation.