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Analog Electronics Question on Inverting Amplifier

The value of Vo(t) for given Vi(t) in the inverting amplifier is:
Inverting Amplifier

A

Vo(t)=−Vi(t)RfRV_o(t)=-V_i(t) \frac{R_f}{R}

B

Vo(t)=+Vi(t)RfRV_o(t)=+V_i(t) \frac{R_f}{R}

C

Vo(t)=−Vi(t)RRfV_o(t)=-V_i(t) \frac{R}{R_f}

D

Vo(t)=+Vi(t)RRfV_o(t)=+V_i(t) \frac{R}{R_f}

Answer

Vo(t)=−Vi(t)RfRV_o(t)=-V_i(t) \frac{R_f}{R}

Explanation

Solution

The correct option is (A): Vo(t)=−Vi(t)RfRV_o(t)=-V_i(t) \frac{R_f}{R}