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Question

Physics Question on Wheatstone Bridge

The value of unknown resistance (x) for which the potential difference between B and D will be zero in the arrangement shown, is :

A

3Ω3 \, \Omega

B

9Ω9 \, \Omega

C

6Ω6 \, \Omega

D

42Ω42 \, \Omega

Answer

6Ω6 \, \Omega

Explanation

Solution

In the given arrangement, we observe a Wheatstone Bridge.
For the bridge to be balanced:

14V Circuit

VABVAD=VBCVCD.\frac{V_{AB}}{V_{AD}} = \frac{V_{BC}}{V_{CD}}.

Substituting values from the circuit:

126+x=0.50.5.\frac{12}{6 + x} = \frac{0.5}{0.5}.

Simplify:

12(0.5)=(6+x)(0.5).12(0.5) = (6 + x)(0.5).

6=3+0.5x    x=6Ω.6 = 3 + 0.5x \implies x = 6 \, \Omega.

Final Answer: x=6Ωx = 6 \, \Omega.