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Question: The value of the ‘spin only’ magnetic moment for one of the following configuration is \(2.84\)BM. T...

The value of the ‘spin only’ magnetic moment for one of the following configuration is 2.842.84BM. The correct one is

A

d4d^{4} (in strong ligand field)

B

d4d^{4} (in weak ligand field)

C

d3d^{3} (in weak as well as in strong fields)

D

d5d^{5} (in strong ligand field)

Answer

d4d^{4} (in strong ligand field)

Explanation

Solution

Spin only magnetic moment

=n(n+2)B.M= \sqrt{n(n + 2)}B.M

Where, n = no. of unpaired electrons.

Given, n(n+2)=2.84\sqrt{n(n + 2)} = 2.84

Or, n (n + 2 ) =8.0656= 8.0656

Or, n = 2

In an octahedral complex, for a d4d^{4}configuration in a strong filed ligand, number of unpaired electrons = 2