Question

The value of the integral is -

• A. n
• B. 2n + sin t + cos t
• C. cos t
• D. sin t – cos t + 4n + 1

Answer 1

Answer: (D)

sin t – cos t + 4n + 1

Answer 2

Since the period of |sin x| + |cos x| is p/2 so

=

2n $\int _ { 0 } ^ { \pi / 2 } ( | \sin x | + | \cos x | ) d x$ +

= 2n $\int _ { 0 } ^ { \pi / 2 } ( \sin x + \cos x ) d x$ +$\int _ { 0 } ^ { t } ( \sin x + \cos x ) d x$

= (2n) (2) + sin t – cos t + 1 = (4n + 1) + sin t – cos t.