Question
Mathematics Question on Some Properties of Definite Integrals
The value of the integral −4π∫4π2−cos2xx+4πdx is :
A
123π2
B
6π2
C
33π2
D
63π2
Answer
63π2
Explanation
Solution
I=4−π∫4π2−cos2xx+4πdx
x→−x
I=−4π∫4π2−cos2x−x+4πdx
(1)+(2)
2I=4−π∫4π2−cos2x2πdx
I=4π⋅20∫4π2−cos2xdxdx
I=4π⋅20∫4π2(1+tan2x)−(1−tan2x)(1+tan2x)dx
I=4π0∫13t2+1dt
⇒I=23πtan−13
I=63π2