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Question

Mathematics Question on Integrals of Some Particular Functions

The value of the integral aaxex21+x2dx\int\limits_{-a}^{a} \frac{xe^{x^2}}{1+x^{2}} dx is

A

ea2e^{a^2}

B

00

C

ea2e^{-a^2}

D

aa

Answer

00

Explanation

Solution

Since, xex21+x2\frac{xe^{x^2}}{1+x^{2}} is an odd function.