Question

The value of the integral $\int\limits^6_3\frac{\sqrt{x}}{\sqrt{9-x}+\sqrt x}dx$ is

• A. $\frac{3}{2}$
• B. 2
• C. 1
• D. $\frac{1}{2}$

Answer 1

Answer: (A)

$\frac{3}{2}$

Answer 2

The correct option is (A): $\frac{3}{2}$