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Question

Mathematics Question on Integration

The value of the integral ∫1−sin⁡xcos⁡2xdx\int\frac{1-\sin x}{\cos^2 x}dx is :

A

secx - tanx + C, Where C is an arbitrary constant.

B

tanx - secx + C, Where C is an arbitrary constant.

C

secx tanx + C, Where C is an arbitrary constant.

D

tanx + secx + C, Where C is an arbitrary constant.

Answer

tanx - secx + C, Where C is an arbitrary constant.

Explanation

Solution

The correct option is (B) :tanx - secx + C, Where C is an arbitrary constant.