Question

The value of the integral $\int e^x (logx + \frac{1}{x})dx$ is:

• A. $e^xlog x + C$, Where C is a constant.
• B. $e^{-x}log x + C$, Where C is a constant.
• C. $\frac{e^x}{x} + C$, Where C is a constant.
• D. $\frac{e^{-x}}{x} + C$, Where C is a constant.

Answer 1

Answer: (A)

$e^xlog x + C$, Where C is a constant.

Answer 2

The correct option is (A): $e^xlog x + C$, Where C is a constant.