Question

The value of the integral $\int _ { - 1 } ^ { 1 } \log \left[ x + \sqrt { x ^ { 2 } + 1 } \right] d x$ is

• A. 0
• B. log 2
• C. log 1/2
• D. None of these

Answer 1

Answer: (A)

0

Answer 2

is a odd function i.e. $f ( - x ) = - f ( x )$

⇒ $f ( x ) + f ( - x ) = 0$ ⇒ I = 0.