Question
Mathematics Question on integral
The value of the integral ∫−22(ex∣x∣+1)∣x3+x∣dx is equal to:
A
5e2
B
3e–2
C
4
D
6
Answer
6
Explanation
Solution
I=∫−22(ex∣x∣+1)∣x3+x∣dx.....(i)
I=∫−22(ex∣x∣+1)∣x3+x∣dx.....(ii)
2I=∫−22∣x3+x∣dx
2I=2∫02(x3+x)dx
I=∫02(x3+x)dx
= (416+24)−0
= 4+2=6
Hence, the correct option is (D): 6