Question
Question: The value of the determinant \(\left| \begin{matrix} 1 & a & b + c \\ 1 & b & c + a \\ 1 & c & a + b...
The value of the determinant 111abcb+cc+aa+bis.
A
a+b+c
B
(a+b+c)2
C
0
D
1+a+b+c
Answer
0
Explanation
Solution
Δ=111abcb+cc+aa+b=(a+b+c)111111b+cc+aa+b
(C2→C2+C3)
= 0, (∵C1≡C2).