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Question

Mathematics Question on Trigonometric Functions

The value of tan3Atan2AtanAtan3A - tan2A - tanA is equal to

A

tan3Atan2AtanAtan3A \,tan2A \,tanA

B

tan3Atan2AtanA-tan3A \,tan2A \,tanA

C

tanAtan2Atan2Atan3Atan3AtanAtanA\, tan2A -tan2A \,tan3A - tan3A \,tanA

D

None of these

Answer

tan3Atan2AtanAtan3A \,tan2A \,tanA

Explanation

Solution

tan3A=tan(2A+A)tan3A = tan\left(2A + A\right) tan3A=tan2A+tanA1tan2AtanA\Rightarrow tan3A=\frac{tan\,2A+tan\,A}{1-tan\,2A\,tan\,A} tan3Atan3Atan2AtanA\Rightarrow tan3A - tan3A \,tan2A\, tanA =tan2A+tanA = tan2A + tanA tan3Atan2AtanA\Rightarrow tan3A - tan2A - tanA =tan3Atan2AtanA = tan3A\, tan2A\, tanA