Solveeit Logo

Question

Mathematics Question on Trigonometric Functions

The value of tan1tan2tan3tan89tan1^{\circ}\, tan2^{\circ}\, tan3^{\circ} \ldots \, tan89^{\circ} is

A

00

B

11

C

12\frac{1}{2}

D

Not defined

Answer

11

Explanation

Solution

tan1tan2tan3tan89tan\,1^{\circ} \cdot tan2^{\circ} \cdot tan3^{\circ} \ldots \, tan89^{\circ} =(tan1tan89)(tan2tan88)(tan44tan46)tan45=\left(tan\,1^{\circ}\,tan\,89^{\circ}\right)\left(tan\,2^{\circ}\,tan\,88^{\circ}\right)\ldots\left(tan\,44^{\circ}\,tan\,46^{\circ}\right)tan\,45^{\circ} =(tan1cot1)(tan2cot2)tan45=111=1=\left(tan\,1^{\circ}\,cot1^{\circ}\right)\left(tan2^{\circ}\,cot2^{\circ}\right)\ldots tan\,45^{\circ}=1\cdot1 \ldots 1=1