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Question

Mathematics Question on Inverse Trigonometric Functions

The value of tan(cos-1x) is:

A

1x\frac{1}{x}

B

1−x2x\frac{\sqrt{1-x^2}}{x}

C

1+x2x\frac{\sqrt{1+x^2}}{x}

D

x1−x2\frac{x}{\sqrt{1-x^2}}

Answer

1−x2x\frac{\sqrt{1-x^2}}{x}

Explanation

Solution

The correct option is(B):1−x2x\frac{\sqrt{1-x^2}}{x}